25 Jun 2021
x˙=y+x(ay+z)y˙=1−bx2+yzz˙=x−x2−y2\begin{align*}\dot{x}&=y + x(ay + z)\\\dot{y}&=1 - bx^2 + yz\\\dot{z}&=x - x^2 - y^2\end{align*} x˙y˙z˙=y+x(ay+z)=1−bx2+yz=x−x2−y2
In the above demo, a=2.07,b=1.79.a = 2.07, b = 1.79.a=2.07,b=1.79.