25 Jun 2021
x˙=sin(y)−bxy˙=sin(z)−byz˙=sin(x)−bz\begin{align*}\dot{x}&=\sin(y) - bx\\\dot{y}&=\sin(z)-by\\\dot{z}&=\sin(x)-bz\end{align*} x˙y˙z˙=sin(y)−bx=sin(z)−by=sin(x)−bz
In the above demo, b=0.1998.b = 0.1998.b=0.1998.